I applied online. The process took 2 months. I interviewed at Schibsted (Oslo) in Nov 2017
Interview
The interview process was excessively long - I think they could make the whole process a little shorter, but the recruiter and everybody else that interviewed me were friendly and professional.
Interview questions [5]
Question 1
Initial interview with the recruiter asking about why I wanted to work at Schibsted, my background and also my salary
Presential meeting with the management and some members of my future team, asking about my experience how to behave in some hypothetical work scenarios
I applied through a recruiter. The process took 2 weeks. I interviewed at Schibsted (Barcelona) in Jan 2017
Interview
It was a very simple and smooth process, talking first with the recruiter on the phone a few times and after that a face to face with the head of software development and the product owner. I was hired on the spot after that,
I applied through a recruiter. The process took 1 week. I interviewed at Schibsted (Barcelona) in Dec 2016
Interview
It consisted in 1 Screener phone interview
1 Coding test at home
4 Whiteboard onsite interview with other engineers
After a hiring committee the make a decision
No behaviour questions I did not meeting with the team I will work with, so no actual feeling if I will fit in
Interview questions [4]
Question 1
Coding skills:
1. Print christmas tree
2. Whiteboard Insertion sort
3. Implement LRU policy in cash
Design chat system, interviewer starts with simplest scenario (2 clients connected) and continue adding constrains (Frontend, Backend, Mobile Notification service (google)) to test scalability knowledge
Logical Problem:
1. Minimize number of racesto find the 3 fastest over 25 horses
2. Two robots on a line the have to meet, they land on a platform and the same command is applied to both of them ate the same time, commands: Right(), Left(), pause(), onPlatform()
CS Fundamental
1. Implement Fibonacci
2. Form a given position traverse all accesible positions
3. Find is a word in an Anagram of another
3 Missing number in a consecutive array -> sum[1...N] = n*(n-1)/2