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explain your framework structure. WAP to print only non-repeated character from "management". explain dataProvider in testNG. how would you locate a "check availability" button in irctc listed train for selected from and to station (this was the question which I couldn't answer)
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Senior Test Automation Engineer

Interviewed at Publicis Sapient

3.4★
Mar 25, 2020

explain your framework structure. WAP to print only non-repeated character from "management". explain dataProvider in testNG. how would you locate a "check availability" button in irctc listed train for selected from and to station (this was the question which I couldn't answer)

1.Reverse a number 2. Reverse a string using HashMap 3. Oops concept 4. difference between protected and default 5. difference between throw and throws 6. Annotations used in Testng 7. Test case techniques 8. getwindowhandles 9. How to resolve merge conflicts in git hub
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Senior Automation Test Engineer

Interviewed at Wipro

3.6★
Jul 12, 2023

1.Reverse a number 2. Reverse a string using HashMap 3. Oops concept 4. difference between protected and default 5. difference between throw and throws 6. Annotations used in Testng 7. Test case techniques 8. getwindowhandles 9. How to resolve merge conflicts in git hub

Round 1:- Telephonic round with collabedit -All basic and tricky question related to dns, shell , pattern, linux, python , debugging and puzzle Round 2:- face2face Technical round with 1 person-Clear -same as round 1 but explained on board. Round 3:- Technical round with 2 person -Programming skill check , Program writting for sorting, occurance and tricky and mathematical puzzle. Round 4: :-Technical round 2nd Question:-"Write a program to grep the pattern from the file and return the line number which has maximum 1. 0110101010010 1101010010101 0110101111111 1111111111100 0100101010010 1000001010100 I wrote:- import io r=open("file.txt",'w+') r.write('0110101010010\n1101010010101\n0110101111111\n1111111111100\n0100101010010\n1000001010100') r.close() index=0 count=0 linenumber=0 val='' for i in open("file.txt",'r'): num1count=1 linenumber+=1 for j in range(len(i)): print i[j] if i[j] is '1': num1count+=1 if count<num1count: index=linenumber count=num1count val=i print 'highest 1 index is ',index, 'and value is ',val Question 3:- Can you optimize this.? I tried to solve using pattern.search. with one for loop. I was not able to recall the syntax of it hence just explain the logic. Question 4:Can you further optimize this? I tried using re.match but i was not able to find the line number for highest number of 1. Question 5:- Can you further optimize. " I replied, This is what i am able to think as of now."
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Software Development Engineer In Test Senior Automation

Interviewed at Akamai

4.3★
Apr 1, 2017

Round 1:- Telephonic round with collabedit -All basic and tricky question related to dns, shell , pattern, linux, python , debugging and puzzle Round 2:- face2face Technical round with 1 person-Clear -same as round 1 but explained on board. Round 3:- Technical round with 2 person -Programming skill check , Program writting for sorting, occurance and tricky and mathematical puzzle. Round 4: :-Technical round 2nd Question:-"Write a program to grep the pattern from the file and return the line number which has maximum 1. 0110101010010 1101010010101 0110101111111 1111111111100 0100101010010 1000001010100 I wrote:- import io r=open("file.txt",'w+') r.write('0110101010010\n1101010010101\n0110101111111\n1111111111100\n0100101010010\n1000001010100') r.close() index=0 count=0 linenumber=0 val='' for i in open("file.txt",'r'): num1count=1 linenumber+=1 for j in range(len(i)): print i[j] if i[j] is '1': num1count+=1 if count<num1count: index=linenumber count=num1count val=i print 'highest 1 index is ',index, 'and value is ',val Question 3:- Can you optimize this.? I tried to solve using pattern.search. with one for loop. I was not able to recall the syntax of it hence just explain the logic. Question 4:Can you further optimize this? I tried using re.match but i was not able to find the line number for highest number of 1. Question 5:- Can you further optimize. " I replied, This is what i am able to think as of now."

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