Round 1:- Telephonic round with collabedit -All basic and tricky question related to dns, shell , pattern, linux, python , debugging and puzzle Round 2:- face2face Technical round with 1 person-Clear -same as round 1 but explained on board. Round 3:- Technical round with 2 person -Programming skill check , Program writting for sorting, occurance and tricky and mathematical puzzle. Round 4: :-Technical round 2nd Question:-"Write a program to grep the pattern from the file and return the line number which has maximum 1. 0110101010010 1101010010101 0110101111111 1111111111100 0100101010010 1000001010100 I wrote:- import io r=open("file.txt",'w+') r.write('0110101010010\n1101010010101\n0110101111111\n1111111111100\n0100101010010\n1000001010100') r.close() index=0 count=0 linenumber=0 val='' for i in open("file.txt",'r'): num1count=1 linenumber+=1 for j in range(len(i)): print i[j] if i[j] is '1': num1count+=1 if count<num1count: index=linenumber count=num1count val=i print 'highest 1 index is ',index, 'and value is ',val Question 3:- Can you optimize this.? I tried to solve using pattern.search. with one for loop. I was not able to recall the syntax of it hence just explain the logic. Question 4:Can you further optimize this? I tried using re.match but i was not able to find the line number for highest number of 1. Question 5:- Can you further optimize. " I replied, This is what i am able to think as of now."
