There were questions about how you reacted to certain circumstances in the past (for me in university projects since I had never worked in the field before), questions about your general way of thinking and also logical problems with no obvious right or wrong answer. The whole process was actually really interesting !
Detailed process of API Integration?
What work are you most proud of?
1- we are given two strings S and T consisting of N and M characters , respectively, and you would like to check whether they might have been obtained as OCR scans of the same text. for example, both strings "A2Le" and "2pl1" could have been obtained as scans of the word "Apple" (but also as scans of the word "Ample"). Both strings "a10" and "10a" could have been obtained as scans of the word "abbbbbbbbba" (but also from many other strings of length 11, starting and ending with "a") . on the other hand, string "ba1" and "1Ad" could not have been obtained from the same text since the second letter of each text is different. so for "A2Le" and "2pL1" we return true. for "a10" and "10a" we return true. for "ba1" and "1Ad" we return false. for "3x2x" and "8" we return false. 2- we have a function like this in java : public String solution(String S) { } String S is consisting of letters A, B, C, D. the string can be transformed either by removing a letter A together with an adjacent letter B , or by removing letter C together with an adjacent letter D . the function should return any string that can be obtained from S by repeatedly applying the described transformation to the point that cannot be further transformed. example 1 : given "CBACD" the function may return "C" . because one of the possible sequence would be : "CBACD" -> "CBA" -> "C" example 2: given "CABABD" the function may return an empty string because one of the possible sequence would be : "CABABD" -> "CABD" -> "CD" -> "" example 3 : "ACBDACBD" the function returns "ACBDACBD" because no operation can be applied to string S . the length of string is within the range of [0 .. 250000] 3- we have a function like this in kotlin : fun solution(A: IntArray, B: IntArray, X: Int, Y: Int): Int { } A and B are intArrays contain values within 1 to 100. values of A and B are coordinations like this (x,y) and they have the same length. the X and Y make one coordination like (X,Y). now if (X,Y) are in the range of +20 or -20 of any of the values in A and B return the index of that pair. example 1 : A = [100, 200, 100] , B = [50,100,100] , X=100 , Y = 70 the answer is 0 . example 2: A = [100,200,100] , B = [50,100,100] , X=100 , Y = 100 the answer is 2 .
Managing background tasks and concurrency
Android architecture and jetpack libraries
Basic data-structure & algorithms
asked all basic android and java questions. asked kotlin, jetpack components, work manager, room db, live data, job scheduler, coroutine, sealed class, scope functions, launch modes of activity
Android Launch, Kotlin coroutines, OOPS concepts
English comprehension, logical thinking, coding
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