I applied through an employee referral. I interviewed at Infosys (Hyderabad) in May 2026
Interview
2 rounds of Technical Interview including DSA and MERN concepts.
DSA was medium level sliding window question. 2nd round was heavily focused on react internals , optimization and monitoring techniques
Interview questions [1]
Question 1
In First round , DSA longest substring without repeating characters.
in 2nd eventough it was MERN , interviewer only focused on React and ended interview without asking other questions.
I applied online. The process took 2 months. I interviewed at Infosys (Hyderabad) in Aug 2024
Interview
One round of Coding assessment. If shortlistes the one round of interview.
The coding round involves 3 questions one ia easy, 2 nd is medium and last one is hard.
Interview questions [1]
Question 1
Coding question, Longest palindromic substring and some technical questions based on resume
I applied online. The process took 2 months. I interviewed at Infosys (Visakhapatnam) in Sep 2025
Interview
It’s the HWI route. Initially, I was given the OA on July 12th, and the interview was scheduled for September 15th. I got a slot, and the interview began with two coding questions on the Infosys Wingspan portal. From there, they asked us to solve any one of the four questions. They only gave us 45 minutes to solve, and I managed to solve one. From there, he looked at my resume and asked questions in depth.
Interview questions [1]
Question 1
You are given an integer array g of length n, where g[i] (1 ≤ i ≤ n) represents the next station you
must go to from station i. There are n stations, numbered from 1 to n. It is guaranteed that every
station eventually reaches station 1. Define the cost of a station i as the number of steps
required to reach station 1 starting from station i (cost[1] = 0, and for i > 1, cost[i] = 1 +
cost[g[i]]). Return the sum of the costs of all stations.
Example 1:
Input: g = [1,1,2,3]
Output: 6
Explanation: Station 1 → cost 0, Station 2 → cost 1, Station 3 → cost 2, Station 4 → cost 3.
Total = 6.
Example 2:
Input: g = [3,1,2]
Output: 3
Explanation: Station 1 → cost 0, Station 2 → cost 1, Station 3 → cost 2. Total = 3.
Example 3:
Input: g = [2,1,1]
Output: 2
Explanation: Station 1 → cost 0, Station 2 → cost 1, Station 3 → cost 1. Total = 2.